Calculate ΔH0 for the reaction between ethene and water to form ethyl alcohol from the following data: ΔcH0C2H5OH(l)=−1368kJ ΔcH0C2H4=−1410kJ Does the calculated ΔH0 represent the enthalpy of formation of liquid ethanol?
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Solution
the heat of combustion of ethanol and ethane is given:
C2H5OH+3O2→2CO2+3H2OΔcH0=−1368kJ ...(1)
C2H4+3O2→2CO2+2H2OΔcH0=−1410kJ ....(2)
reverse (1) equation and add to (2) equation we get a equation
C2H4+H2O→C2H5OHΔH0==1368kJ−1410kJ=−42kJ
Thus, ΔH0 represents the enthalpy of formation of ethanol.