Calculate ΔH for the following reaction: 8Al(s)+3Fe3O4(s)→4Al2O3(s)+9Fe(s)
Given ΔHf for Al2O3(s) and Fe3O4(s) are -1669.8 kJ and -1120.9 kJ respectively.
A
-3316.5 kJ
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B
-3650.4 kJ
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C
-2650.4 kJ
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D
None of the above
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Solution
The correct option is A -3316.5 kJ Given, ΔHf(Al2O3(s))=−1669.8kJ and ΔHf(Fe3O4(s))=−1120.9kJ
the reaction is 8Al(s)+3Fe3O4(s)→4Al2O3(s)+9Fe(s)
as per convention ΔHf(Fe(s))=0kJ,ΔHf(Al(s))=0kJ
We know that ΔH for a reaction =∑ΔHf(products)−∑ΔHf(reactants)