wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Calculate ΔH for the following reaction:
8Al(s)+3Fe3O4(s)4Al2O3(s)+9Fe(s)
Given ΔHf for Al2O3(s) and Fe3O4(s) are -1669.8 kJ and -1120.9 kJ respectively.

A
-3316.5 kJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
-3650.4 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-2650.4 kJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A -3316.5 kJ
Given, ΔHf(Al2O3(s))=1669.8 kJ and ΔHf(Fe3O4(s))=1120.9 kJ

the reaction is 8Al(s)+3Fe3O4(s)4Al2O3(s)+9Fe(s)

as per convention
ΔHf(Fe(s))=0 kJ, ΔHf(Al(s))=0 kJ

We know that ΔH for a reaction =ΔHf(products)ΔHf(reactants)

=4ΔHf(Al2O3(s))+9ΔHf(Fe(s))3ΔHf(Fe3O4(s))8ΔHf(Al(s))

=4×1669.8+3×1120.9
=3316.5 kJ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon