339

You visited us 339 times! Enjoying our articles? Unlock Full Access!

Electric Field Due to a Dipole Along the Equatorial Line

Calculate E...

Question

Calculate $E^{0}$ and E for the cell $S n | S n^{2 +} (1 M) | | P b^{2 +} (10^{- 3} M) | P b, E^{0} (S n^{2 +} | S n) = - 0.14 V E^{0} (P b^{2 +} | P b) = - 0.13$ V. Is cell representation correct?

Open in App

Solution

$S n ╱ {s n}^{+ 2} 1 M / / {p b}^{+ 2} (10^{- 3} M) / p b E^{0} ({s n}^{+ 2} / s n) = - 0.14 v E^{0} ({p b}^{+ 2} / p b) = - 0.13 v S n + {p b}^{+ 2} ⟼ p b + {S n}^{+ 2} E^{0} c e l = E^{0} c a t h o d e - E^{0} a n o d e = 0.13 - (- 0.14) = 0.01 E c e l = E^{0} c e l \frac{0.059}{n} log \frac{(1) (1)}{10^{- 3}} = 0.01 - \frac{0.059}{2} log 1000 = 0.01 - 0.0885 = - 0.0785 v H e r e E c e l i s n e g a t i v e S o, R e p r e s e n t a t i o m i s w r o n g$

Suggest Corrections

Similar questions

E^{0}

E

S n | {S n}^{2 +} (1 M) ∥ {P b}^{2 +} (10^{- 3} M) | P b, E^{0} ({S n}^{2 +} / S n) = - 0.14 V, E^{0} ({P b}^{2 +} / P b) = - 0.13 V

P b + S n^{2 +} \to P b^{2 +} + S n

\frac{[P b^{2 +}]}{[S n^{2 +}]}

E_{c e l l} = 0

E_{P b / P b^{2 +}}^{\circ} = 0.13 v o l t

E_{S n^{2 +} / S n}^{\circ} = - 0.14 v o l t

S n (s) | S n^{2 +} (a q ., 1 M) | | P b^{2 +} (a q ., 1 M) | P b (s)

\frac{[S n^{2 +}]}{[P b^{2 +}]}

E_{\frac{S n^{2 +}}{S n}}^{\circ} = - 0.14 V; E_{\frac{P b^{2 +}}{P b}}^{\circ} = - 0.13 V, \frac{2.303 R T}{F} = 0.06 V)

P b + S n^{2 +} \to P b^{2 +} + S n

E^{o}

P b \to P b^{2 +}

E^{o}

S n^{2 +} + 2 e^{-} \to S n

E^{o}

P b + S n^{2 +} \to P b^{2 +} + S n

P b \to P b^{2 +}, E^{o} = 0.13 V

S n^{2 +} + 2 e^{-} \to S n; E^{o} = - 0.14 V

Join BYJU'S Learning Program