Calculate Ecell for - Fes - Fe2- 0-1 M- -Fe3- 0-01 M- Fe2- 1 M- Pt- T - 298 K-Given E0Fe3- - Fe2- - -0-771 V- E0Fe2- - Fe - -0-41 V-

The correct option is A 1.09 V Fe → Fe^+2 + 2e^ (Fe^+3 + e → Fe^+2 ) × 2 Fe + 2 Fe^+ 3→ 3 Fe^+2 E_cell = E^o_cell 0.059n log [.Fe^+2 ...

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Faraday's Second Law

Calculate E...

Question

Calculate $E_{c e l l}$ for :
$F e_{(} s) | F e^{2 +} (0.1 M) | | F e^{3 +} (0.01 M) | F e^{2 +} (1 M) | P t$ , T = 298 K.
Given $E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.771 V, E_{F e^{2 +} / F e}^{0} = - 0.41 V$ .

1.09 V

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1.18 V

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2.18 V

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2.36 V

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Solution

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E_{F e^{2 +} / F e}^{0} = - 0.441 V

E_{F e^{3 +} / F e^{2 +}}^{0} = 0.771 V

F e + 2 F e^{3 +} \to 3 F e^{2 +}

F e | F e^{2 +} | | F e^{3 +} | F e

F e | F e^{2 +} | | F e^{3 +}, F e^{2 +} | P t

F e | F e^{3 +} | | F e^{3 +}, F e^{2 +} | P t

E_{c e l l} = 0.2905 V

Z n (s) + F e^{2 +} (a q) 0.01 M \to Z n^{2 +} 0.1 M (a q) + F e (s)

E_{F e^{3 +} / F e}^{0} = 0.036 V, E_{F e^{2 +} / F e}^{0} = - 0.439 V

F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)

E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

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