Question

Calculate energy of 2 moles of photons of radiation whose frequency is $5\times {10}^{14}Hz$

• A. $3.313\times {10}^{-19}J$
• B. $6.626\times {10}^{-19}J$
• C. $3990.2kJmo{l}^{-1}$
• D. $6790.2kJmol-1$

Answer 1

The correct option is C $3990.2kJmo{l}^{-1}$

Energy (E) of one photon = E = hv

Where, $h=6.626\times {10}^{-34}Js$
$E=5\times {10}^{14}Hz\times 6.626\times {10}^{-34}Js=3.313\times {10}^{-19}J$
Energy of 2 mole of photon = $3.313\times {10}^{-19}J\times 2\times 6.022\times {10}^{23}mo{l}^{-1}$
$=3990.2kJmol-1$