Question

Calculate energy of one mole of photon of radiations whose frequency is $5\times {10}^{14}Hz$.

Answer 1

Energy of one photon is given by the expression $E=hv$

$E=(6.636\times {10}^{34}J{s}^{-1}\times 5\times {10}^{14}{s}^{-1})$

$=33.18\times {10}^{20}$J

One mole of photon $=6.023\times {10}^{23}$ photons

Therefore, Energy of one mole of photon $=(6.023\times {10}^{23}\times 33.18\times {10}^{-20}J)=199.84\times {10}^3$ J

Energy of one mole of photon $=199.84$ kJ