Calculate mean deviation about mean and median for given observations {1, 1, 4, 2, 6, 100, 150, 200, 400}

103.4, 93.55

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102.4, 93.55

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1024, 92.55

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102.4, 92.54

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Solution

The correct option is A
103.4, 93.55

Mean for given Observations $= \frac{1 + 1 + 4 + 2 + 6 + 100 + 150 + 200 + 400}{9}$

$\frac{864}{9} = 95$

median for given $= {1, 1, 2, 4, 6, 100, 150, 200, 400}$

$= 6$

Absolute deviations about mean $= {94, 94, 91, 93, 89, 5, 55, 105, 305}$

Mean deviation about mean $= \frac{94 + 94 + 91 + 93 + 89 + 5 + 55 + 105 + 305}{9}$

$M D (¯ x) = 103.4$

Mean deviation about median $= \frac{5 + 5 + 2 + 4 + 0 + 94 + 144 + 194 + 394}{9}$

$M D (m) = 93.55$

Suggest Corrections

Marks	$100 - 110$	$110 - 120$	$120 - 130$	$130 - 140$	$140 - 150$
Frequency	$4$	$6$	$5$	$3$	$2$

Size	4	6	8	10	12	14	16
Frequency	2	4	5	3	2	1	4

Wages(Rs)	$20$	$18$	$16$	$14$	$12$	$10$	$8$	$6$
Frequency	$2$	$4$	$9$	$18$	$27$	$25$	$14$	$1$

Class	$0 - 10$	$10 - 20$	$20 - 30$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$
Frequency	$5$	$4$	$3$	$2$	$2$	$1$	$1$