Calculate Mean Deviation about Median
Class $5$ $15$ $25$ $35$ $45$
Frequency $5$ $10$ $20$ $5$ $10$

7

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8

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19

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9

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Solution

The correct option is D $9$
$X i$ $f$ $c . f$ $| X i - M |$ $f i \times | X i - M |$
5 5 5 20 100
15 10 15 10 100
25 20 35 (Median Class) 0 0
35 5 40 10 50
45 10 50 20 200
$\sum f i | X i - M |$ $= 450$

Rank of Median $=$ $\frac{N}{2}$ th Observation and $(\frac{N}{2} + 1)$ th observation
$= 25 t h$ and $26 t h$ observations

Median $=$ $\frac{25 + 25}{2}$ $= 25$

Mean Deviation about Median $=$ $\frac{1}{N} \sum f i | X i - M |$ = $\frac{450}{5}$ $= 9$

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Similar questions

Variable( $x$ )	$10$	$15$	$20$	$25$	$30$	$35$	$40$	45
Frequency( $f$ )	$7$	$3$	$8$	$5$	$6$	$8$	$4$	9

Class	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$
Frequency	$5$	$10$	$20$	$5$	$10$

Marks	0-5	5-10	10-15	15-20	20-25	25-30	30-35	35-40	40-45	45-50
Frequency	3	5	7	8	10	11	14	19	15	13

CI	$0 - 5$	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$	$30 - 35$	$35 - 40$	$40 - 45$	$45 - 50$
$f$	$9$	$13$	$6$	$12$	$9$	$6$	$10$	$15$	$6$	$4$

Class interval	$5$	$15$	$25$	$35$	$45$
Frequency	$5$	$3$	$9$	$12$	$6$

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