Calculate n-factor of Na3PO4 in the following reaction.
Na3PO4+3BaCl2 → 6NaCl+Ba3(PO4)2
3
This is the type of reaction where none of the atoms involved undergo a change in their oxidation states.
A simple way to find the n-factor of Na3PO4 in such reactions would be to find the amount of cationic charge replaced per molecule.
In 2Na3PO4, we have6Na+
So, Na3PO4 has 3Na+
Na+ can be cosider to be similar to H+in H3PO4 (just an analogy)