CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

calculate number of electrons in Fe having

n+ l+M=2

Open in App
Solution

The value of n+l+m=2 can be obtained in the following combinations
  1. n=2 l=1 m=-1. This 2px orbital and there will be two electrons in this subshell
  2. n=2 l=0 m=0. This is 2s orbital and there will be two electrons in this orbital
So there are four electrons in total that will have n+l+m=2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electron distribution in different orbits
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon