Calculate percentage of water of crystallization in : $M g S O_{4} . 7 H_{2} O$ [Atomic masses of $M g = 24, S = 32, O = 16, H = 1]$

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Solution

Molecular weight of water $H_{2} O = 2 (1) + 16 = 18$ g/mol.
Molecular weight of $M g S O_{4} \cdot 7 H_{2} O = 24 + 32 + 4 (16) + 7 (18) = 246$ g/mol
Percent of water of crystallisation in $M g S O_{4} \cdot 7 H_{2} O = \frac{7 \times 18}{246} \times 100 = 51.2$ %.

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