Question

Calculate pH for 0.01 N $(CaOH{)}_2$

• A. 12
• B. 10
• C. 11
• D. 8

Answer 1

The correct option is A 12

$Ca(OH{)}_2$ is not having much solubility in water, but whatever amount dissolves, almost completely dissociates into $C{a}^{+2}$ and $O{H}^{-}$
$Ca(OH{)}_2$ $\to$ $C{a}^{2+}$ + $2O{H}^{-}$
${10}^{-2}N$ $0$ $0$
0 $\frac{1}{2}+{10}^{-2}$ ${10}^{-2}$
$\therefore \left[OH\right]={10}^{-2}\times 1$ gm equivalent/lit
$={10}^{-2}$ gm mole / lit
pOH = 2
pH = 12