Calculate resonance energy of N 2 O from the following data Hence- H - N 2 O -82 kJ mol -1Assume structure N - N - OBE of N - N bond -950 kJ mol -1 N - N bond -420 kJ mol -1O - O bond -500 kJ mol -1 O - N bond -610 kJ mol -1A- -170 kJ mol -1B- -356 kJmol -1C- -88 kJ mol -1D- -190 kJmol -1

The correct option is C 88 kJ mol^ 1We calculate theoretical value of _fH^∘ of N_2O. Difference of experimental and theoretical value gives resonance energy ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Heat of Reaction

Calculate res...

Question

Calculate resonance energy of $N_{2} O$ from the following data
Hence, $△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}$
Assume structure $N^{Θ} = N^{⨁} = O$
BE of $(N \equiv N) b o n d = 950 k J m o l^{- 1}$
$(N = N) b o n d = 420 k J$ mol $^{- 1}$
$O = O) b o n d = 500 k J m o l^{- 1}$
$(O = N) b o n d = 610 k J m o l^{- 1}$

- 170 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 356 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 88 k J m o l^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 190 k J m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $- 88 k J m o l^{- 1}$
We calculate theoretical value of $△_{f} H^{\circ}$ of $N_{2} O$ . Difference of experimental and theoretical value gives resonance energy
$N_{2} (g) + \frac{1}{2} O_{2} (g) \to N^{Θ} = N^{⨁} = O (g) △_{f} H^{\circ} (N_{2} O) = [(B E)_{N \equiv N} + \frac{1}{2} (B E)_{O = O}] - [(B E)_{N = N} + (B E)_{N = O}] = [950 + \frac{500}{2}] - [420 + 610] = 170 k J$
$△_{f} H^{\circ}$ (experimental) = $82 k J$
Thus resosance energy of $N_{2} O = 82 - 170 = - 88$ $k J m o l^{- 1}$

Suggest Corrections

Similar questions

Q. Calculate resonance energy of

N_{2} O

from the following data
Hence,

△ H^{\circ} (N_{2} O) = 82 k J m o l^{- 1}

Assume structure

N^{Θ} = N^{⨁} = O

BE of

(N \equiv N) b o n d = 950 k J m o l^{- 1}

(N = N) b o n d = 420 k J

mol

^{- 1}

O = O) b o n d = 500 k J m o l^{- 1}

(O = N) b o n d = 610 k J m o l^{- 1}

Q. Calculate the resonance energy of

N_{2} O

from the following data:

△_{f} H^{o} o f N_{2} O = 82 k J m o l^{- 1},

N \equiv N, 946 k J m o l^{- 1}; N = N, 418 k J m o l^{- 1};

O = O, 498 k J m o l^{- 1}; N = O, 607 k J m o l^{- 1}

Q. Calculate the resonance energy of

N_{2} O

from the following data:

△_{f} H^{\circ}

N_{2} O = 82 k J m o l^{- 1}

, standard bond enthalpies of

N = N, N = N, O = O

and

N = O

bonds are

946, 418, 498

and

607 k J m o l^{- 1}

respectively.

Q. Use thye given data to calculate the resonance energy of

N_{2} O

(Δ H_{f}^{o}

N_{2} O = 82 k J m o l^{- 1})

, Bond energies of NΞN, N=N,O=O and N=O bonds are 946 ,418 ,498 and 607 kj mol-1 respectively.
Choose the correct option.

Q. Calculate the resonance energy of

N_{2} O

from the following data:

Δ H_{f}^{o}

N_{2} O = 134 K J {m o l}^{- 1}

Bond energy of

N - O, N = O, N \equiv N

and

O = O

bonds are

222, 607, 946

and

498 k J {m o l}^{- 1}

respectively.

Join BYJU'S Learning Program

Calculate resonance energy of N2O from the following data Hence, △H∘(N2O)=82 kJmol−1 Assume structure NΘ=N⨁=O BE of (N≡N) bond=950 kJmol−1 (N=N) bond=420 kJ mol−1 O=O) bond=500 kJmol−1 (O=N) bond=610 kJmol−1