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Question

Calculate resonance energy of N2O from the following data
Hence, H(N2O)=82 kJmol1
Assume structure NΘ=N=O
BE of (NN) bond=950 kJmol1
(N=N) bond=420 kJ mol1
O=O) bond=500 kJmol1
(O=N) bond=610 kJmol1

A
170 kJmol1
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B
356 kJmol1
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C
88 kJmol1
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D
190 kJmol1
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Solution

The correct option is C 88 kJmol1
We calculate theoretical value of fH of N2O. Difference of experimental and theoretical value gives resonance energy
N2 (g)+12O2 (g)NΘ=N=O (g)fH(N2O)=[(BE)NN+12(BE)O=O][(BE)N=N+(BE)N=O]=[950+5002][420+610]=170 kJ
fH (experimental) = 82 kJ
Thus resosance energy of N2O=82170=88 kJmol1

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