Calculate standard enthalpy of formation for benzene from the following data- C 6 H 6 - - 15 2 O 2 g - 6CO 2 g - 3H 2 O - - H o -3267KJ - f H o CO 2 -393-5 KJ mol -1 - f H o C 2 O -285-8 KJ mol -1

C _ 6 H _ 6( ℓ #160; ) #160; + 15 2 O _ 2( g ) #160; ⟶ 6CO _ 2( g ) #160; + 3H _ 2 O _( ℓ #160; ) #160; Δ H ^ o Here, H^o=∑ _fH^o(pr ...

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Heat of Formation

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Question

Calculate standard enthalpy of formation for benzene from the following data.
$C_{6} H_{6 (ℓ)} + \frac{15}{2} O_{2 (g)} ⟶ {6 C O}_{2 (g)} + {3 H}_{2} O_{(ℓ)} {Δ H}^{o} = - 3267 K J$
$Δ_{f} H^{o} ({C O}_{2}) = - 393.5 K J {m o l}^{- 1}$
$Δ_{f} H^{o} (C_{2} O) = - 285.8 K J {m o l}^{- 1}$

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300 K

C_{6} H_{6} (ℓ) + \frac{15}{2} O_{2} (g) ⟶ {6 C O}_{2} (g) + {3 H}_{2} O (ℓ); Δ H = - 3271 k J

Δ U

1.5

27^{\circ} C

C_{6} H_{6} (l) + \frac{15}{2} O_{2} (g) \to {3 H}_{2} O (l) + {6 C O}_{2} (g)

C_{6} H_{6} (l)

H_{2} O (l)

{C O}_{2} (g)

(Δ_{f} G^{0} (H)_{(a q)}^{+} = 0)

H_{2} O (l) ⟶ H^{+} (a q) + O H^{-} (a q); Δ H = 57.32 k J

H_{2} (g) + \frac{1}{2} O_{2} (g) ⟶ H_{2} O (l); Δ H = - 286.20 k J

O H^{-}

25^{o} C

- 3267 k J / m o l, - 393.5 k J / m o l

- 285.8 k J / m o l

{C H}_{4} (g) + 2 O_{2} (g) ⟶ {C O}_{2} (g) + 2 H_{2} O (l)

{C H}_{4}, {C O}_{2}

H_{2} O

74.8 k J {m o l}^{- 1}, - 393.5 k J {m o l}^{- 1}, - 286 k J {m o l}^{- 1}

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