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Avogadro's Number

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Question

calculate the amount of aluminium hydroxide produced by reacting 200g of aluminium chloride with ammonium hydroxide.

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Solution

$A l C l_{3} + 3 N H_{4} O H \to A l (O H)_{3} + 3 N H_{4} C l 1 m o l e o f a l u m i n i u m c h l o r i d e r e s u l t s i n t o t h e f o r m a t i o n o f 1 m o l e o f a l u m i n i u m h y d r o x i d e . S o, n u m b e r o f m o l e s i n 200 g o f a l u m i n i u m c h l o r i d e = \frac{m a s s}{m o l e c u l a r m a s s} = \frac{200}{133.5} m o l e s S o, \frac{200}{133.5} m o l e s o f A l (O H)_{3} a r e f o r m e d . M a s s o f \frac{200}{133.5} m o l e o f A l (O H)_{3} = \frac{200}{133.5} \times m o l e c u l a r m a s s = \frac{200}{133.5} \times 78 = 116.85 g$

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Similar questions

^{Blanced chemical equation for the reaction}

^{Aluminium chloride + Ammonium hydroxide -- Aluminium hydroxide +Ammonium chloride}

A l C l_{3}

reacts with 120 g of NaOH to give aluminium hydroxide. The produced aluminium hydroxide reacts with 3 mol of

H_{2} S O_{4}

to give aluminium sulphate. Calculate the moles of aluminium sulphate produced in the reaction.

A l C l_{3} + 3 N a O H \to A l (O H)_{3} + 3 N a C l

2 A l (O H)_{3} + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 6 H_{2} O

A l C l_{3}

reacts with 120 g of NaOH to give aluminium hydroxide. The produced aluminium hydroxide reacts with 3 mol of

H_{2} S O_{4}

to give aluminium sulphate. Calculate the moles of aluminium sulphate produced in the reaction.

A l C l_{3} + 3 N a O H \to A l (O H)_{3} + 3 N a C l

2 A l (O H)_{3} + 3 H_{2} S O_{4} \to A l_{2} (S O_{4})_{3} + 6 H_{2} O

Q. Write formulae of the following compounds.
Sodium phosphate, Aluminium chloride, Calcium oxide, Potassium nitrate, Ammonium hydroxide

Q. Metals like zinc and aluminium react with sodium hydroxide to produce ____ gas.

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