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Percentage Composition

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Question

Calculate the amount of $C a C O_{3}$ in grams having percentage purity $25 %$ that produces $0.56$ litre of $C O_{2}$ at STP on heating?

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Solution

We know,
$C a C O_{3} \to C a O + C O_{2}$
$0.56 L C O_{2} = \frac{0.56}{22.4} m o l = \frac{1}{40} m o l C O_{2}$
So, amount of $C a C O_{3}$ required $= \frac{1}{40} \times 100 \times \frac{100}{25} g = 10 g$
Since percentage purity is = 25%

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