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Question

Calculate the amount of H2 required to completely react with 112 litres of Cl2 at STP to produce HCl:

A
8 g
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B
14 g
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C
10 g
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D
None of these
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Solution

The correct option is C 10 g
H2+Cl22HCl
moles of Cl2 = mol of H2
moles of Cl2 taken=11222.4=5 mol
So, mol of H2 required=5 mol
Amount of H2 required = Moles × Molar mass
Mass of H2 required = 5 mol×2 g/mol=10 g

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