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Question

Calculate the amount of ice that will separate out on cooling a solution containing 50 g of ethylene glycol in 200g of water to 9.3°C.

Molal depression constant for water is 1.86 K kg/mol

A
8.80g
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B
6g
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C
7.50g
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D
8.91g
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Solution

The correct option is D 8.91g
Molal depression constant = Depression in Kelvin per mole of solute present in kg of solvent.

molecular mass of Ethylene Glycol = C2H6O2 = 62 gm/mole
Number of moles/kg of water = 50/621000/200 = 4 moles/kg
Actual depression in freezing point temperature: 1.86°K4 = 7.44°K

Specific heat of Ice = 2J/gm°K
The heat released from 200gm of water(ice) due to the lowering of temperature
=7.442200=2,976J
Latent heat of fusion of ice = 334kJ/kg=334J/gm

Amount of ice that will melt away due to availability of 2,976J:
= 2,976/334
= 8.91 gm

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