Calculate the amount of ice that will separate out on cooling a solution containing 50 g of ethylene glycol in 200 g water from 0∘C to −9.3∘C. (Kf for water = 1.86 K kg mol−1).
ΔTf=9.30C
Kf= 1.86 K kg mol−1
molar mass of ethylene glycol, M=62 g/mol
let mass of remaining liquid water is W.
Now, ΔTf=Kf×w×1000m×W
9.3=1.86×50××100062×W
W=161.29 g
Hence, amount of ice separated from 200 g water =200−161.29=38.71 g.
Hence, (d) is the correct option.