Calculate the amount of ice that will separate out on cooling a solution containing 50g of ethylene glycol in 200g of water till −9.3∘C(Kf for water =1.86 Kkgmol−1)
A
161.29g
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B
38.71g
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C
200g
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D
31.7g
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Solution
The correct option is B38.71g ΔT=1000×Kf×wM.M×W 9.3=1000×1.86×5062×W
W = 161.29 g
Ice seperated = 200 - 161.29
= 38.71g