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Question

Calculate the amount of Ni needed (in g) in the Mond's process given below
Ni+4CONi(CO)4
If CO used in this process is obtained through a process, in which 6 g of carbon is mixed with 44 g CO2.(Ni=59 u)

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Solution

CO is obtained through the following process:
C+CO22CO
Finding the limiting reagent:
Given moles of C = (612)=0.5
Moles of CO2=4444=1

moles of Cstoichiometric coefficient=0.51=0.5

moles of CO2stoichiometric coefficient=11=1


So, C is limiting reagent
CO formed = 1 moles
Now, moles of Ni needed to react with this
1 mole of CO =14 according to the stoichiometry.
Mass of Ni = 14×59=14.75 g.

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