Calculate the amount of work done in rotating a dipole, of dipole moment $3 \times 10^{- 8} c m$ , from its position of stable equilibrium to the position of unstable equilibrium, in a uniform electric field of intensity $10^{4} N / C$ .

Open in App

Solution

$P = 3 \times 10^{- 8} C m; E = 10^{4} N / C$
At stable equilibrium $(θ_{1}) = 0^{\circ}$
At unstable equilibrium $(θ_{2}) = 180^{\circ}$
Work done in a rotating dipole is given by:
$W = P E (cos θ_{1} - cos θ_{2}) = (3 \times 10^{- 8}) (10^{4}) [cos 0^{\circ} - cos 180^{\circ}] = 3 \times 10^{- 4} [1 - (- 1)]$
$W = 6 \times 10^{- 4} J$ .

Suggest Corrections

Similar questions

Q. Calculate the amount of work done in turning an electric dipole of dipole moment

3 \times 10^{- 8} C

-m from its position of unstable equilibrium to the position of stable equilibrium in a uniform electric field of intensity

10^{3} N C^{- 1}

A dipole is present in an electrostatic field of magnitude 106N/C. If the work done in rotating it from its position of stable equilibrium to its position of unstable equilibrium is 2×10~23J, then find the magnitude of the dipole moment of this dipole.

A dipole with a dipole moment of magnitude p is in stable equilibrium in an electrostatic field of magnitude E. Find the work done in rotating this dipole to its position of unstable equilibrium.

Q. calculate the amount of work done in rotating a dipole from stable equilibrium to unstable equilibrium and state whether energy is released or consumed?

Q. The work done in rotating a bar magnet of magnetic moment

M

from its unstable equilibrium position to its stable equilibrium position in a uniform magnetic field

B

Join BYJU'S Learning Program

Calculate the amount of work done in rotating a dipole, of dipole moment 3×10−8cm, from its position of stable equilibrium to the position of unstable equilibrium, in a uniform electric field of intensity 104N/C.

P=3×10−8Cm;E=104N/CAt stable equilibrium (θ1)=0∘At unstable equilibrium (θ2)=180∘Work done in a rotating dipole is given by:W=PE(cosθ1−cosθ2)=(3×10−8)(104)[cos0∘−cos180∘]=3×10−4[1−(−1)]W=6×10−4J.

Calculate the amount of work done in rotating a dipole, of dipole moment $3 \times 10^{- 8} c m$ , from its position of stable equilibrium to the position of unstable equilibrium, in a uniform electric field of intensity $10^{4} N / C$ .