Question

Calculate the angular velocity and linear velocity of a minute hand of length $10cm$.

Answer 1

Given:-

$T=60min.=(60\times 60)s=3600s$

$l=10cm=0.1m$

To Find :

angular velocity $\left(\omega \right)=?$

Linear velocity $\left(v\right)=?$

Solution :

$\omega =\frac{2\pi }{T}=\frac{2\times 3.142}{3600}$

$\therefore \omega =1.744\times {10}^{-3}rad/s$

$\Rightarrow v=r\omega =0.1\times 1.745\times {10}^{-3}$

$\therefore v=1.745\times {10}^{-4}m/s$