Question

Calculate the area and perimeter of the given figure where the circular parts are semicircle.

Answer 1

R.E.F image

Area of semicircle =$\frac{\pi r^2}{2}$

Area of $c_2=\frac{\pi (7{)}^2}{2}=\frac{22}{7}\times \frac{49}{2}=77cm$

{Diameter=14}

Area of $c_1=\frac{\pi (7{)}^2}{2}=77c{m}^2$

Area of rectangle ABDB $=l\times b=14\times 8=112c{m}^2$

Area of shaded region $=A\left(ABDC\right)-A(c_1+A(c_2\left)\right)$

$=A\left(ABDC\right)=112c{m}^2$.

Perimeter of semicircle $=\pi r$

Perimeter of shaded region $=\pi r_1+8+8\pi r_2$

$=\pi (7+7)+16=14\pi +16$

$=44+16=60cm$