Calculate the area of shaded part of the figure given below

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Solution

Area of AFGI = Area of CDHI
$\begin{matrix} = ℓ \times b = 25 \times 3.4 = 85 m^{2} \end{matrix}$
Area of curved area = area of outer half circle - area of inner half circle
$\begin{matrix} = \frac{1}{2} π r_{1}^{2} - \frac{1}{2} π r_{2}^{2} = \frac{1}{2} π [{(\frac{19.1}{2})}^{2} - {(\frac{12.3}{2})}^{2}] = \frac{π}{2} [91.2 - 37.82] = 83.8066 m^{2} ∴ t o t a l a r e a = 2 \times A r e a o f A F G T + 2 \times A r e a o f c u r v e d r e g i o n = 2 \times 85 + 2 \times 83.8066 = 337.6132 m^{2} \end{matrix}$

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