Question

Calculate the binding energy of an alpha-particle. Given mass of proton $=1.0073$ a.m.u., mass of neutron $=1.0087$ a.m.u., mass of $\alpha$-particle$=4.0015$a.m.u.

Answer 1

Binding Energy $=△m{c}^2$

$△m=$ mass of $\alpha$ particle $-$ mass of total number of proton and neutron

$=4.00150-2(1.00728+1.00867)=4.00150-4.0319=-0.0304u$

$E=△m{c}^2$$=0.0304\times 931MeV=28.30MeV$