Calculate the change in volume of gases when 1 mole of PH3 decomposed at STP according to given reaction: PH3(g)→14P4(g)+32H2(g)
A
22.7
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B
74×22.7
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C
34×22.7
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D
72×22.7
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Solution
The correct option is C34×22.7 When 1 mole of PH3 decomposes at STP, the change in the number of moles of gaseous species is Δn=14+32−1=34 When we multiply Δn with 22.4, we get the change in volume of gases. The change in volume of gases =34×22.4 L.