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Question

Calculate the coefficient of correlation of the following data by Spearman's rank correlation method:

X192412231916Y92220142218

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Solution

X YR1R2(R1R2)D2D1993.51+2.56.25242265.5+0.50.2512201439231452+3919223.55.52416182311N=16D2=29.50

Here number 19 is repeated twice in series X and number 22 is repeated twice in series Y. Therefore, in X, m = 2 and in Y, m = 2.

Rank Coefficient of Correlation (rk)=

16[D2+112(m31m1)+112(m32m2)+.....]N3N

D2=29.50;

=16[29.50+112(232)+112(232)]636

=16[29.50+0.5+0.5]201

=16×30.5210

=1183210=10.871

= 0.129

Rank Coefficient of Correlation = 0.129. There is a very low degree of positive correlation.


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