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Question

Calculate the degree of hydrolysis (h) of a 0.1 M sodium acetate solution at 298 K.
Given: Ka=1.8×105

A
8.42×105
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B
7.42×106
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C
7.42×105
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D
8.42×106
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Solution

The correct option is C 7.42×105
Hydrolysis constant for a salt of weak acid and strong base is given as:
Kh=KwKa=1×10141.8×105=5.5×1010

Degree of hydrolysis is given as:
h=KhC=5.5×10100.1=(55×1010)1/2=7.42×105

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