Calculate the - H f o of C 6 H 12 O 6 s from the following data- - H comb - C 6 H 12 O 6 s - -2816 kJ-mol - H f o of CO2g-393-5 kJ-mol - H f o of H2Ol-285-9 kJ-mol

The correct option is C 1260 kJ/mol Enthalpy of formation of C_6H_12O_6 = 6 × heat of formation of CO_2 + 6 × heat of formation of ...

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Heat of Formation

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Question

Calculate the $Δ H_{f}^{o}$ of $C_{6} H_{12} O_{6} (s)$ from the following data:
$Δ H_{c o m b} [C_{6} H_{12} O_{6} (s)] = - 2816 k J / m o l$
$Δ H_{f}^{o}$ of ${C O}_{2} (g) = - 393.5 k J / m o l$
$Δ H_{f}^{o}$ of $H_{2} O (l) = - 285.9 k J / m o l$

- 126.0 k J / m o l

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- 1260 k J / m o l

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- 1220 k J / m o l

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- 160 k J / m o l

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{Δ H}_{f}^{o}

C_{6} H_{12} O_{6} (s)

Δ H_{c o m b .}

C_{6} H_{12} O_{6} (s) = - 2816 k J {m o l}^{- 1}

{Δ H}_{f}^{o}

{C O}_{2} (g) = - 393.5 J {m o l}^{- 1}

{Δ H}_{f (H_{2} O)}^{o} = - 285.9 k J {m o l}^{- 1}

C_{6} H_{12} O_{6}

H_{2} O

298 K

C_{6} H_{12} O_{6} + 6 O_{2} (g) ⟶ 6 {C O}_{2} (g) + 6 H_{2} O

Δ H^{o} = - 2820 k J {m o l}^{- 1}; Δ S^{o} = 210 J K^{- 1} {m o l}^{- 1}

Δ H_{f}^{o}

{C H}_{3} C N (g) = 88 k J / m o l

Δ H_{f}^{o}

C_{2} H_{6} = - 84 k J / m o l

Δ H_{s u b l i m a t i o n}^{o}

C (g r) = 717 k J / m o l

N_{2} (g)

H_{2} (g)

946

436 k J / m o l

B . E (C - H) = 410 k J / m o l

C - C

C \equiv N

α

C_{12} H_{22} O_{11} (a q) + H_{2} O (l) ⟶ 2 C_{6} H_{12} O_{6} (a q)

Δ_{f} H^{o} (H_{2} O, l) = - 285.85 k J

{m o l}^{- 1}

Δ_{f} H^{o} (C_{6} H_{12} O_{6}, a q) = - 1263.1 k J

{m o l}^{- 1}

Δ_{f} H^{o} (C_{12} H_{22} O_{11}, a q) = - 2238.3.1 k J

{m o l}^{- 1}

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