Calculate the effective nuclear charge of the last electron in an atom whose configuration is 1s22s22p63s23p5.
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Solution
Z = 17 Z∗=Z−S = 17 - [(0.35 × No. of other electrons in nth shell)] + (0.85 × No. of electrons in (n - 1)th shell) + (1.00 × total number of electrons in the inner shells) =17−[(0.35×6)+(0.85×8)+(1×2)] =17−10.9=6.1