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Question

Calculate the electrostatic potential energy of an electron-proton system of hydrogen atom. In the first Bohr orbit of hydrogen atom, the radius of the orbit is 5.3×1011m :


A
4.35×1018J
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B
2.175×1018J
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C
4.35×1019J
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D
2.175×1019J
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Solution

The correct option is C 4.35×1018J
The electrostatic P.E. of proton electron pair is 14πϵ0e2r where r is the separation between the proton and electron and e is electron's charge.
Since the charges are opposite in sign, P.E. is negative.
Given, r=5.3×1011m
Hence, P.E.=(9×109)×(1.6×1019)25.3×1011=4.35×1018J

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