wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Calculate the Q-values of the following fusion reactions:
(a) H12+H12H13+H11
(b) H12+H12He23+n
(c) H12+H13He24+n.
Atomic masses are
m(H12)=2.014102u,m(H13)=3.016049u,m(H23e)=3.016029u,m(H24e)=4.002603u.

Open in App
Solution

(a) Q=2×m H12-mH33+mH13c2 =(4.028204-4.023874)×931 MeV =4.05 MeV(b) Q=2×m H12-(m H23+mn)c2 =[4.028204-4.024694)×931 =0.00351×931 =3.25 MeV(c) Q=m H12+m H13-m He14-mnc2 =(2.014102+3.016049-4.002603-1.008665)×931 =17.57 MeV

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermochemistry
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon