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Byju's Answer
Standard XII
Chemistry
EMF
Calculate the...
Question
Calculate the emf of the cell,
C
d
|
C
d
2
+
(
0.001
M
)
|
|
F
e
2
+
(
0.6
M
)
|
F
e
a
t
25
∘
C
.
The standard reduction potential of
C
d
/
C
d
h
2
+
and
F
e
/
F
e
2
+
electrodes are -0.403 and -0.441 volt respectively.
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Solution
E
=
E
o
−
0.0591
n
l
o
g
C
d
2
+
F
e
2
+
E
=
(
0.403
−
0.441
)
−
0.0591
2
l
o
g
0.001
0.6
E
=
0.044
v
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Similar questions
Q.
The standard reduction potential for
F
e
2
+
|
F
e
and
S
n
2
+
|
S
n
electrodes are
−
0.44
V
and
−
0.14
V
respectively. For the cell reaction,
F
e
2
+
+
S
n
→
F
e
+
S
n
2
+
, the standard
E
.
M
.
F
.
is:
Q.
The standard electrode potential (reduction) of
P
t
/
F
e
2
−
,
F
e
3
+
and
P
t
/
S
n
4
+
,
S
n
2
+
are 0.77 V and 0.15 v respectively at
25
o
C The standard EMF of the reaction
S
n
4
+
+
2
F
e
2
+
→
S
n
2
+
+
2
F
e
3
+
is:
Q.
Standard electrode potentials of
F
e
2
+
+
2
e
−
→
F
e
and
F
e
3
+
+
3
e
−
→
F
e
are
−
0.440
V
and
−
0.036
V
respectively. The standard electrode potential
(
E
o
)
for
F
e
3
+
+
e
−
→
F
e
2
+
is:
Q.
The emf of the cells obtained by combining zinc and copper electrodes of the Daniell cell with calomel electrodes are
1.083
v
o
l
t
and
−
0.018
v
o
l
t
respectively at
25
∘
C
. If the reduction potential of normal calomel electrode is
+
0.28
volt, find he emf of the Daniell cell.
Q.
The standard reduction potential
E
o
for half reactions are,
Z
n
→
Z
n
2
+
+
2
e
−
;
E
o
=
−
0.76
V
F
e
2
+
+
2
e
−
→
F
e
;
E
o
=
+
0.41
V
The emf of the cell reaction;
F
e
2
+
+
Z
n
→
Z
n
2
+
+
F
e
is:
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