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Question

Standard electrode potentials of Fe2++2eFe and Fe3++3eFe are 0.440V and 0.036V respectively. The standard electrode potential (Eo) for Fe3++eFe2+ is:

A
0.476V
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B
0.404V
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C
+0.404V
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D
+0.772V
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Solution

The correct option is D +0.772V
Fe2++2eFe E01=0.440V ......(1)

Fe3++3eFe E02=0.036V ......(2)

we know that ΔG0=nFE0cell

to obtain the resultant equation, (2)(1)

that is-Fe3++eFe2+

ΔG0net=ΔG2ΔG1
which gives :
nFE0net=n2FE02(n1FE01)
n2=3
n1=2
For the resultant equation, n=1

Putting all the equation in the above obtained equation for the net Gibbs free energy we get,
E0net=0.108+0.88

=+0.772

hence option D is correct.





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