Given standard electrode potentials- Fe2 - 2e- Fe- E- - -0-440 V Fe3- - 3e- Fe- E- - -0-036 VThe standard electrode potential E- for Fe3- - e- Fe2- is-

The correct option is B +0.772 V We know, #160; G^∘ = nFE^∘ Fe^2+ + 2e^ → Fe G^∘ = 2× F× ( 0.440V) = 0.880 F ...... (1) Fe^3+ + 3e ...

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Nernst Equation

Given standar...

Question

Given standard electrode potentials, $F e^{2} + 2 e^{-} \to F e, E^{\circ} = - 0.440 V$
$F e^{3 +} + 3 e^{-} \to F e, E^{\circ} = - 0.036 V$
The standard electrode potential $(E^{\circ})$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

+ 0.772 V

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- 0.772 V

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+ 0.417 V

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- 0.414 V

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Solution

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Similar questions

F e^{2 +} + 2 e^{-} \to F e

F e^{3 +} + 3 e^{-} \to F e

- 0.440 V

- 0.036 V

E^{0}

F e^{3 +} + e^{-} \to F e^{2 +}

Given standard electrode potentials:

$F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V$

The standard electrode potential $E^{o}$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

F e^{2 +} + 2 e^{-}

⟶

F e; E^{o} = - 0.440 V

F e^{3 +} + 3 e^{-}

⟶

F e; E^{o} = - 0.036 V

(E^{o}

F e^{3 +} + e^{-}

\to

F e^{2 +}

F e^{2 +} + 2 e^{-} \to F e

F e^{3 +} + 3 e^{-} \to F e

- 0.440 V

- 0.036 V

(E^{o})

F e^{3 +} + e^{-} \to F e^{2 +}

F e^{3 +} + 3 e^{-} \to F e; E^{\circ} = - 0.036 v o l t

F e^{2 +} + 2 e^{-} \to F e; E^{\circ} = - 0.440 v o l t

E^{\circ}

F e^{3 +} + e^{-} \to F e^{2 +}

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