Given- standard electrode potentials- Fe3- - 3e- Fe- E- - -0-036 volt Fe2- - 2e- Fe- E- - -0-440 voltThe standard electrode potential E- for Fe3- - e- Fe2- is-

The correct option is A 0.772 volt Applying G = nFE Fe^2+ + 2e^ → Fe G = 2× F× ( 0.440V) = 0.88F .... (i) Fe^3+ + 3e^ → Fe G = 3× F ...

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Given, standa...

Question

Given, standard electrode potentials:
$F e^{3 +} + 3 e^{-} \to F e; E^{\circ} = - 0.036 v o l t$
$F e^{2 +} + 2 e^{-} \to F e; E^{\circ} = - 0.440 v o l t$
The standard electrode potential $E^{\circ}$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

0.772 v o l t

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- 0.404 v o l t

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0.440 v o l t

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- 0.772 v o l t

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Solution

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Similar questions

{F e}^{3 +} + {3 e}^{-} ⟶ F e; E^{o} = - 0.036 v o l t

{F e}^{2 +} + {2 e}^{-} ⟶ F e; E^{o} = - 0.440 v o l t

E^{o}

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}

F e^{2} + 2 e^{-} \to F e, E^{\circ} = - 0.440 V

F e^{3 +} + 3 e^{-} \to F e, E^{\circ} = - 0.036 V

(E^{\circ})

F e^{3 +} + e^{-} \to F e^{2 +}

F e^{2 +} + 2 e^{-} \to F e, E^{o} = - 0.440

F e^{3 +} + 3 e^{-} \to F e, E^{o} = - 0.036

(E^{o})

F e^{3 +} + e^{-} \to F e^{2 +}

F e^{2 +} + 2 e \to F e

F e^{3 +} + 3 e \to F e

- 0.440

- 0.036

(E^{0})

F e^{3 +} + e \to F e^{2 +}

Given standard electrode potentials:

$F e^{3 +} + 3 e^{-} \to F e; E^{0} = - 0.036 V$

$F e^{2 +} + 2 e^{-} \to F e; E^{0} = - 0.440 V$

The standard electrode potential $E^{o}$ for $F e^{3 +} + e^{-} \to F e^{2 +}$ is:

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