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Question

Calculate the emf of the cell
Cr|Cr3+(0.1 M)||Fe2+(0.01 M)|Fe
(Given: ECr3+/Cr=0.75 volt;EFe2+/Fe=0.45 volt).

A
1.231 volt
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B
1.361 volt
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C
2.461 volt
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D
2.561 volt
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Solution

The correct option is A 1.231 volt
Cr|Cr3+(0.1M)||Fe2+(0.01M)|Fe
ECr2+|Cr=0.75V;EFe2+/Fe=0.45V
2Cr3++3Fe3Fe2++2Cr
Ecell=EcellRTnFlnQ=1.28.314×2986×96500ln(0.01)3(0.1)2=1.20.00428×ln(104)=1.20.009855×log(104)=1.2+0.0394=1.2394

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