Calculate the emf of the cell

Pt, $H_{2} (1.0 a t m)$ | $C H_{3} C O O H$ (0.1M) || $N H_{3}$ (aq, 0.001M) | $H_{2}$ (1.0 atm), Pt Ka( $C H_{3} C O O H$ ) = $10^{- 5}$ , Kb(NH3) = $10^{- 5}$

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-0.413 V

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Solution

The correct option is B
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Calculate the emf of the cell

Pt, $H_{2} (1.0 a t m)$ | $C H_{3} C O O H$ (0.1M) || $N H_{3}$ (aq, 0.001M) | $H_{2}$ (1.0 atm), Pt Ka( $C H_{3} C O O H$ ) = $10^{- 5}$ , Kb(NH3) = $10^{- 5}$

Calculate the emf of the cell

Pt, $H_{2} (1.0 a t m)$ | $C H_{3} C O O H$ (0.1M) || $N H_{3}$ (aq, 0.001M) | $H_{2}$ (1.0 atm), Pt Ka( $C H_{3} C O O H$ ) = $10^{- 5}$ , Kb(NH3) = $10^{- 5}$