Question

Calculate the empierical formula of the compound containing 37.6% $Na$, 23.1% $Si$ and 39.3% $O$.

$(O=16;Na=23,Si=28)$

• A. $N{a}_{3}Si{O}_3$
• B. $N{a}_{2}Si{O}_3$
• C. $N{a}_{2}Si{O}_4$
• D. $N{a}_{2}Si{O}_2$

Answer 1

The correct option is B $N{a}_{2}Si{O}_3$

given that

$37.6$ grams of $Na$

$23.1$ grams of $Si$

$39.3$ grams of oxygen

moles of $Na=\frac{37.6}{23}=1.63$

moles of $Si=\frac{23.1}{28}=0.825$

moles of $O=\frac{39.3}{16}=2.45$

simplest Ratio is $1:2:3$ $\{Si:Na:O\}$

empierical $\to N{a}_{2}Si{O}_3$