Calculate the empirical formula of the compound containing 37.6 % $N a$ , 23.1% $S i$ and 39.3% $O$ .
$(O = 16; N a = 23, S = 28)$

N a_{2} S i O_{3}

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N a_{2} S i O_{2}

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N a_{3} S i O_{2}

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N a_{4} S i O_{3}

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Solution

The correct option is A $N a_{2} S i O_{3}$
solve given value of this question no of sodium atom is 2
no of silicon atom is 1
no of oxygen atom is 3
so the empirical formula is $N a_{2} S i O_{3}$
so the answer is A

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Similar questions

Q. Calculate the empierical formula of the compound containing 37.6%

N a

, 23.1%

S i

and 39.3%

O

(O = 16; N a = 23, S i = 28)

(a) Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen (O = 16; Na = 23; Si = 28).
(b) The empirical formula of a compound is C₂H₅. It has a vapour density of 29. Determine the relative molecular mass of the compound and hence its molecular formula.

Q. A compound contains 43.4% sodium, 11.3% carbon and 45.3% oxygen.
Determine its empirical formula. (Atomic mass of

N a = 23 C = 12, O = 16

Q. Calculate the formula unit mass (u) of

{N a}_{2} O

A t o m i c m a s s o f N a = 23 u, O = 16 u

Q. A substance on analysis gave the following percentage composition:

N a = 43.4 %, C = 11.3 %

and

O = 45.3 %

. Calculate the empirical weight (Atomic weight in amu of

N a = 23, C = 12, O = 16

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Calculate the empirical formula of the compound containing 37.6 % Na, 23.1% Si and 39.3% O. (O=16; Na=23, S=28)

The correct option is A Na2SiO3 solve given value of this question no of sodium atom is 2 no of silicon atom is 1 no of oxygen atom is 3 so the empirical formula is Na2SiO3 so the answer is A

Calculate the empirical formula of the compound containing 37.6 % $N a$ , 23.1% $S i$ and 39.3% $O$ .
$(O = 16; N a = 23, S = 28)$

The correct option is A $N a_{2} S i O_{3}$
solve given value of this question no of sodium atom is 2
no of silicon atom is 1
no of oxygen atom is 3
so the empirical formula is $N a_{2} S i O_{3}$
so the answer is A