Calculate the empirial formula of a compound having percentage composition; POtassium (K) $26$ $57$

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Solution

$K = \frac{26.57 g}{39.098 g m o l} = 0.68 m o l k$

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A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of the compound. [Pb = 207, O = 16]

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[P b = 207; O = 16]

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