Calculate the energy associated with photon of light having a wavelength 6000 oA. [h= 6.626×10−27ergs]
A
3.313×10−11erg
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B
3.313×10−12erg
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C
3.313×10−13erg
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D
3.313×10−10erg
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Solution
The correct option is B3.313×10−12erg We know that: E=hv=hcλ h=6.626×10−27erg.s c=3×1010cm/s λ=6000oA = 6×10−5cm E=(6.626×10−27)×(3×1010)6×10−5=3.313×10−12erg