Calculate the energy associated with the first orbit of $H e^{+}$ . What is the radius of this orbit ?

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Solution

$E_{n} = - 13.6 z^{2} / n^{2} e V$

For $H e^{+}$ first orbit, n is 1 and z = 2

Thus $E_{n} = - 13.6 \times 4 e V = 54.4 e V$

And radius $= 5.29 \times 10^{- 11} n^{2} / z = 1.32 \times 10^{- 11}$

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Calculate the energy associated with the first orbit of He+. What is the radius of this orbit ?

En=−13.6z2/n2eVFor He+ first orbit, n is 1 and z = 2Thus En=−13.6×4eV=54.4eVAnd radius =5.29×10−11n2/z=1.32×10−11

Calculate the energy associated with the first orbit of $H e^{+}$ . What is the radius of this orbit ?

$E_{n} = - 13.6 z^{2} / n^{2} e V$

For $H e^{+}$ first orbit, n is 1 and z = 2

Thus $E_{n} = - 13.6 \times 4 e V = 54.4 e V$

And radius $= 5.29 \times 10^{- 11} n^{2} / z = 1.32 \times 10^{- 11}$