Question

Calculate the energy in corresponding to light of wavelength $45nm.$

Answer 1

Step 1: Given Data

Wavelength = $45nm$

Step 2: Formula used

$\mathrm{E}=\frac{hc}{\lambda }$

Here,

$h$is the Planck’s constant ($6.62607015\times {10}^{-34}\mathrm{Js}$)

$c$ is the velocity of light ($3\times {10}^8\mathrm{m}/\mathrm{s}$)

$\lambda$ is the wavelength.

Step 3: Calculation of energy

We get this by substituting the known values in the equation,

$\mathrm{E}=\frac{hc}{\lambda }$

$E=\frac{6.62607015\times {10}^{-34}\times 3\times {10}^8}{45\times {10}^{-9}}$

$E=4.42\times {10}^{-18}\text{Joules}$

Therefore, the energy for the given wavelength is $4.42\times {10}^{-18}\text{Joules}$.