Question

Calculate the energy of lowest level in $H{e}^{+}$ and $3^{rd}$ level in $L{i}^{2+}$ ion.

Answer 1

$E_n=-2.18\times {10}^{-18}\left(z^2/n^2\right)J$

energy for lowest level in $H{e}^{+}$ is

$=2.18\times {10}^{-18}\times \left(2^2/1^2\right)=8.72\times {10}^{-18}$

energy for third level in $L{i}^{+}$ is

$=2.18\times {10}^{-18}\times \left(3^2/3^2\right)=2.18\times {10}^{-18}$