Question

Calculate the radius of Bohr's 3rd orbit in $L{i}^{2+}$ ion

Answer 1

Radius of the Bohr's orbit is given by,

$r=\frac{n^2{h}^2}{4{\pi }^{2}mZ{e}^2}$

Substituting values of $h,m,$ $Z=4$ and $n=3$ for lithium and $e$ the electronic charge $r$ may be calculated as,

$r=1.07A^0$