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Question

Calculate the energy of photon (in J) of light having frequency 2.7×1013 s1?

A
2×1021 J
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B
1.7×1020 J
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C
3.4×1021 J
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D
3×1020 J
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Solution

The correct option is B 1.7×1020 J
Given, λ=2.7×1013 s1
Energy of one photon = hv, where h=Planck's constant = 6.626×1034 Js
Energyof photon =6.626×1034×2.7×1013
= 17.89×1021 J
= 1.78×1020 J

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