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Question

Calculate the enthalpy change for the reaction (only magnitude in nearest integer in kj/mol):
2C(s)+2H2(g)+O2(g)CH3CO2H(l)

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Solution

Given reaction
R:2C+2H2+O2CH3CO2H;ΔH=?

From the given table, enthalpies of the following reactions are

R1:C+O2CO2;ΔH1=394kJ/mol

R2:H2+12O2H2O;ΔH2=286kJ/mol

R3:CH3CO2H+2O22CO2+2H2O;ΔH3=876kJ/mol

And

R=R3+2R1+2R2

ΔH=ΔH3+2ΔH1+2ΔH2=+876+2×(394)+2×(286)=484kJ/mol

Answer = 484

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