Question

calculate the equilibrium constant for the oxidation of sulfur dioxide or sulfur trioxide if standard gibbs energy change for the reaction is 141.8 kJ
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Answer 1

$$\begin{gathered} Therelationbetween∆G^{0}andequilibriumcons\tan tis \\ ∆G^0=-2.303RT\log K \\ 141.8\times {10}^3=-2.303\times 8.314\times 298\times \log K \\ \log K=-\frac{141.8\times {10}^3}{2.303\times 8.314\times 298} \\ =-24.8517 \\ K=A.\log (-24.8517) \\ =1.407\times {10}^{-25} \end{gathered}$$